Question 515574
Determine the nature of the solutions of the equation. 
y^2 = 4/5y + 4/7 
y^2 - 4/5y -4/7 = 0 
a = 1
b = -4/5
c = -4/7 
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Find the determinant, Det = b^2 - 4ac
Get rid of fractions first, multiply by 35
y^2 - 4/5y -4/7 = 0
35y^2 - 28y - 20 = 0
Det = 28^2 - 4*35*(-20) = 784 + 2800 = 3584
Det > 0 --> 2 real solutions