Question 515538
A chemist wants to make 44 mL of a 16% acid solution by mixing a 10% acid solution and an 18% acid solution. How many milliliters of each solution should the chemist use? 
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Equation:
acid + acid = acid
0.10x + 0.18(44-x) = 0.16*44
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10x + 18*44 - 18x = 16*44
-8x = -2*44
x = 11 mL (amt. of 10% solution needed)
44-x = 33 mL (amt. of 18% solution needed)
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Cheers,
Stan H.
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