Question 515520
graph the inequality on a plane
    2x+3y <= 6
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1st Solve for "y":
y <= (-2/3)x + 2
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2nd: graph the boundary: y = (-2/3)x + 2
{{{graph(400,400,-10,10,-10,10,(-2/3)x + 2)}}}
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3rd: Since you want y LESS than the boundary, shade
the half-plane BELOW the boundary.
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{{{graph(400,400,-10,10,-10,10,y < (-2/3)x+2)}}}
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Cheers,
Stan H.
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