Question 51583
Sorry, but no cigar!
You do have the first term corect ({{{(5/2)x}}} but the y-intercept (b) is not right.

Let's start with what you have done.
{{{y = (5/2)x + b}}} To find the value of b, you need to substitute the x- and y-coordinates of the given point (2, 1)
{{{1 = (5/2)(2) + b}}} Simplify this.
{{{1 = 5 + b}}} Subtract 5 from both sides of the equation.
{{{-4 = b}}} Now you can write the equation:
{{{y = (5/2)x - 4}}}
Here are the two lines on a graph:
{{{y = (5/2)x+6}}} Red line.
{{{y = (5/2)x-4}}} Green line.
{{{graph(300,200,-5,5,-5,8,(5/2)x+6,(5/2)x-4)}}}