Question 514975
Perhaps you mean meters (m) here, then it makes some sense
:
Denny walks 60 m in one minute, and John travels 210 m in one minute by bike.
 If Denny has already walked 1800 m, how many minutes will it take for John to catch up with Denny by bike assuming Denny continues to walk?
:
We know 60 m/min is Denny's walking speed
and
210 m/min is John's pedaling speed
:
Let t = time for J go catch D
:
Write a distance equation; dist = speed * time
:
J's dist = D's dist + 1800 m
210t = 60t + 1800
210t - 60t = 1800
150t = 1800
t = {{{1800/150}}}
t = 12 min for J to catch D
:
:
You can check this, find the distance each has traveled
J: 210*12 = 2520 m
D: 60* 12 =  720 m
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difference: 1800 m