Question 515219
[(-2xy^-1)^-3] / [(xy^-5)^-8]
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Invert top and bottom to get:
[(xy^-5)^8] / [(-2xy^-1)^3]
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[x^8y^-40]/[-8x^3y^-3]
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= [-x^5]/[8y^37]
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Cheers,
Stan H.
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