Question 515137

Set the equation equal to zero

{{{x3+x^2-4x-4=0}}} Factor the left side of equation

{{{x^2(x+1)-4(x+1)=0}}}

{{{(x+1)(x+2)(x-2)=0}}} Solve the equation setting each factor to zero:

x+1=0 => x=-1; x+2=0 => x=-2, and x-2=0 => x=2

Answer:The solution set is {-2, -1, 1}