<PRE><B>Question 514965</B>
The following table gives the monthly distances in miles driven by a random sample of 16 sales persons: 
2011, 1969, 2396, 2365, 2014, 2184, 2234, 2141, 2419, 2041, 1922, 2616. 2377, 1942, 2227, 2519 
Based on this sample, find a 90% confidence interval for the mean number of miles driven monthly by members of the sales staff, assuming that monthly driving distances are normally distributed. Then complete the table below. 
Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place.
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Sample mean : 2211.0625
ME = 1.645*218.513/sqrt(16) = 89.8635
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What is the lower limit of the confidence interval? sample mean-ME
What is the upper limit of the confidence interval? sample mean+ME
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Cheers,
Stan H.
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