Question 51409
A quadratic equation always produces a parabola.  Let's first substitute each value of x into the equation to get its corresponding y value, or ordered pair.<br>
For x=0, we get {{{y=0^2-5*0+4}}} which simplifies to {{{y=4}}}.  So, our first ordered pair is (0,4).<br>
Using substitution again for x=1 produces {{{y=1^2-5*1+4}}}, which simplifies to {{{y=0}}}, or ordered pair (1,0).<br>
Using the same process for the other values of x (2,3,4) produces ordered pairs (2,-2), (3,-2), and (4,0).<br>
Now we just graph our ordered pairs.
{{{graph(300,200,-5,5,-5,5,x^2-5x+4)}}}