Question 514700
In a bicycle race, Miss Muffet gives Mary Contrary a 500m advantage.
 Also, Miss Muffet agrees to start 15 minutes after Mary Contrary.
 Now, just as the race began, Miss Muffet saw a spider near her tuffet, and took off at 17km/h.
 Mary Contrary takes off at 14km/h.
 How long will it take Miss Muffet to overtake Mary Contrary.
:
The way I interpret all this nonsense is they both took off at the same time, with Contrary starting 500 m ahead of Muffet
:
We are using km/h, change 500 m to .5 km
:
Let t = time required for M to overtake C
:
Write a distance equation: Dist = speed * time
:
M's dist = C's dist + 500m
17t = 14t + .5
17t - 14t = .5
3t = .5
t = {{{.5/3}}}
t = .167 * 60 = 10 minutes (changed hrs to minutes)