Question 513562
1.) sin < 0, tan < 0, what quadrant will both be in? 
2.) Find the exact value of tan theta, given that sin theta = -1/6 and theta is in quadrant IV. 
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1.) sin<0 in quadrants III and IV. tan<0 in quadrants II and IV.
Therefore, sin and tan will be in quadrant IV
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2.) sinx=-1/6=opposite side/hypotenuse
by Pythagorean Theorem, adjacent side=&#8730;(6^2-1)=&#8730;(36-1)=&#8730;35
tanx=opposite side/adjacent side=-1/&#8730;35=-&#8730;35/35