Question 514633

Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function.



The x-coordinates of vertex is? 
This is what I did so far. 
f(x)= -2x^2 + 2x + 3
= -2(x^2 -x) + 3
= -2 (x^2 - x + 1/4 - 1/4) + 3
= -2 (x^2 - x + 1/4) + -2(-1/4) + 3
= -2 (x^2 -x +1/4) + and this is where I get totally lost and confused. 
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= -2 (x^2 - x + 1/4) + -2(-1/4) + 3
You were almost done
= -2(x - 1/2)^2 + 7/2
The line of symmetry is x = 1/2
The vertex is (1/2,7/2), a maximum
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A better method is:
The LOS is x = -b/2a = -2/-4
x = 1/2
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The vertex is (1/2,f(1/2)) = (1/2,7/2)
And you're done.

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To graph this, and others, dl the FREE graph software at
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Use Insert, then enter the function