Question 514319
flagpole was broken 10 ft. from the ground and the top is falling the pole 15 ft. from the base of the pole. 
What was the height of the flagpole?
:
This forms a right triangle, we can solve with: c^2 = a^2 + b^2
where
a = 10
b = 15
c = the additional height of the flag pole above the break
:
c^2 = 10^2 + 15^2
c^2 = 100 + 225
c = {{{sqrt(325)}}}
c = 18.03 ft
therefore the height of the flagpole: 18.03 + 10 = 28.03 ft