Question 514144
How many ounces of a 10% alcohol solution must be added to 40 ounces of a 25% solution to reduce it to a 15% solution?
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Equation:
alcohol + alcohol = alcohol
0.10x + 0.25*40 = 0.15(x+40)
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Multiply thru by 100:
10x + 25*40 = 15x + 15*40
5x = 10*40
x = 80 oz (amt. of 10% solution needed)
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Cheers,
Stan H.
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