<PRE><B>Question 513998</B>
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Let *[tex \Large l] represent the length.  Then if the length is 5 feet greater than the width, the width must be 5 feet smaller than the length, so the width is *[tex \Large l\ -\ 5].  The perimeter is two times the length plus two times the width.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2l\ +\ 2(l\ -\ 5)\ =\ 310]


Solve for *[tex \Large l]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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