Question 513933
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Positive case:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 8\ +\ p\ \geq\ 0]


then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 8\ +\ p\ =\ 2p\ -\ 3]


Solve for *[tex \Large p]


Negative case:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 8\ +\ p\ <\ 0]


then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 8\ +\ p\ =\ -(2p\ -\ 3)]


Solve for *[tex \Large p]


Check both solutions.  If either (or both) result in a false statement, then that solution is extraneous and should be discarded.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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