Question 513871
Let {{{ b }}} = the speed of train B
Then {{{ b - 6 }}} = the speed of train A
Let {{{ t }}} = time for both trains
Train A:
(1) {{{ 230 = ( b - 6 )*t }}}
Train B:
(2) {{{ 260 = b*t }}}
-------------
(1) {{{ 230 = b*t - 6t }}}
Substitute (2) into (1)
(1) {{{ 230 = 260 - 6t }}}
(1) {{{ 6t = 260 - 230 }}}
(1) {{{ 6t = 30 }}}
(1) {{{ t = 5 }}}
-----------
From (2)
(2) {{{ b = 260/t }}}
(2) {{{ b = 260/5 }}}
(2) {{{ b = 52 }}}
and
(1) {{{ 230 = ( b - 6 )*t }}}
(1) {{{ 230 = ( b - 6 )*5 }}}
(1) {{{ b - 6 = 46 }}}
----------------
Train A travels 46 mi/hr
Train B travels 52 mi/hr