Question 513817
A father is x years old and the son is y.
the sum of their ages is 58.
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x + y = 58
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five years ago the father was five times as old as the son
(x-5) = 5(y-5)
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find the age of the two men
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x = 58-y
Substitute for "x" and solve for "y":
(58-y-5) = 5(y-5)
-y+53 = 5y-25
6y = 78
y = 13 yrs (son's age now)
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Solve for "x"
x + y = 58
x + 13 = 58
x = 45 (father's age now)
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Cheers,
Stan H.
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