Question 513762
{{{sin(2x)=-1/2}}} As you know {{{sin(7pi/6)=-1/2}}} and {{{ sin(-pi/6)=-1/2}}}

Therefore the solution is: {{{2x=7pi/6+-2n*pi}}} => {{{x=7pi/12+-n*pi}}}, and

{{{2x=-pi/6+-2n*pi}}} => {{{x=-pi/12+-n*pi}}}, where n=+-1, +-2, ...