Question 513743
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Let *[tex \Large x] represent the measure of the altitude.  Then the measure of the side related to that altitude is *[tex \Large 5x\ +\ 3].  Since we know the area of a triangle is the measure of the base times the measure of the altitude to that base divided by 2, we can write:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{(5x\ +\ 3)x}{2}\ =\ 13]


Which is to say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5x^2\ +\ 3x\ -\ 26\ =\ 0]


Solve the quadratic for *[tex \Large x], discard the extraneous negative root, then calculate *[tex \Large 5x\ +\ 3]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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