Question 513719
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If the slope of the line is *[tex \Large m] and the *[tex \Large y]-intercept is the point *[tex \Large (0,b)], then an equation of the line in slope-intercept form is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ mx\ +\ b]


You already have one point on the line, namely the *[tex \Large y]-intercept, so plot that point.


Select a different value for *[tex \Large x] and substitute that value for *[tex \Large x] in the derived equation.  Do the arithmetic required to calculate the resulting value of *[tex \Large y].  Create the new ordered pair *[tex \Large (x,y)] using the value you chose for *[tex \Large x] and the value you calculated for *[tex \Large y].  Plot this new point.  Construct a line that passes through both of your plotted points.  Hint:  When you choose a value for *[tex \Large x], select a small, non-zero integer value -- it makes the arithmetic easier and less subject to error.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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