<PRE><B>Question 513620</B>
Find the missing coordinates 2x-3y=6:(3, ), ( ,-2), (-1, ), ( ,2)
2x-3y=6: (3,0), (0 ,-2), (-1, -8/3), (6,2)
								
If x=3, then:                     
2(3) – 3y = 6                     
6 – 3y = 6                          
-3y = 6 – 6                              
-3y = 0                                     
-3y/-3 = 0/-3                           
y = 0                                             


If x = -1, then:                     
2(-1) – 3y = 6                     
-2 – 3y = 6                          
-3y = 6 +2                              
-3y = 8                                     
-3y/-3 = 8/-3                           
y = -8/3                                             
 



 If y=-2, then:
2x – 3(-2) = 6
2x + 6 = 6
2x = 6 - 6
2x = 0
2x/2 = 0/2
x = 0


If y=2, then:
2x – 3(2) = 6
2x - 6 = 6
2x = 6 + 6
2x = 12
2x/2 = 12/2
x = 6

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