Question 51362
How do I "simplify" The square root of 1/32? (that is 1/32 inside the radical.)

sqrt(1/32)= [sqrt1] /[ sqrt32]= [sqrt2]/[sqrt64]=[sqrt2]/8
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I have a complicated question and can get so far but I forget how to do this step. The problem starts as 4x^2+x-1/16=0 
Rewrite as:
4(x^2+(1/4)x+?=(1/16+?
Complete the square, as follows:

4(x^2+(1/4)x+(1/8)^2)=(1/16)+4(1/8)^2
4(x+(1/8))^2= 17/16
(x+(1/8))^2=17/64
Take the square root of both sides to get:
x+1/8 = [sqrt17]/8 or x+1/8 = sqrt 17]/8-
x=[-1+sqrt 17]/8 or x=[-1-sqrt 17]/8

Cheers,
Stan H.