Question 51362
(a+b)^2 = a^2+2ab+b^2


4x^2+x-1/16  =  0
 x^2+x/4     = 1/64
 x^2+x/4+1/64= 1/64+1/64
  (x+1/8)^2  = 1/32
   x     =  (1/32)^(1/2)-1/8
         =   1/(16*2)^(1/2)-1/8
         =   1/4*(2)^(1/2)-1/8
         =   2^(1/2)/8-1/8
         =   [2^(1/2)-1]/8
         =    [2^(1/2)-1]/8               or      x   =  {-[2^(1/2)]-1}/8

         =   (1.414.. - 1)/8               or      x   =  (-1.414.. -1)/8
         =   0.414/8                       or      x   =  -2.414/8
         =   0.0517...                      or     x   =  -0.3017