<PRE><B>Question 513518</B>


Let 1st number be F
Then second = F – 5
Also, third = ½F


We then have: F + F – 5 + ½F = 45 
2½F – 5 = 45
2½F = 45 + 5
2½F = 50
5F/2 = 50
5F = 100 ----- Cross-multiplying   
F, or 1st number = 100/5, or {{{highlight_green(20)}}}


2nd number = F – 5, or 20 – 5, or {{{highlight_green(15)}}}


3rd number = ½F, or ½(20), or {{{highlight_green(10)}}}  


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Check
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First + second + third = 45


20 + 15 + 10 = 45 


45 = 45 (TRUE)


Send comments and “thank-yous” to “D” at  MathMadEzy@aol.com</PRE>