Question 513518
Let Numbers are x, y, z

x+y+z=45..............(1)
x=y+5
x-5=y
y=x-5.................(2)
x=2z
x/2=z
z=x/2..................(3)
Put the value of x from (2) and (3) to (1)

x+x-5+x/2=45
2x+x/2=45+5
2x+x/2=50
Multiply by 2 both sides
2*(2x+x/2)=50*2
4x+x=100
5x=100
5x/5=100/5
x=20
Put the value of x in (2) and (3)
y=x-5.................(2)
y=20-5
y=15
z=x/2..................(3)
z=20/2
z=10

So Numbers are 20, 15, 10