Question 513328
Let x = the number
1)	3x + 2  … sum of three times a number increased by two
2)	4( 3x + 2)  … four times the sum of three times a number increased by two
3)	2x – 8 … difference of two times the number decreased by eight
4)	3(2x – 8) … three times the difference of two times the number decreased by eight
So your equation would be:
4(3x + 2) = 3(2x – 8)