Question 513268
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The formula for the perimeter of a rectangle is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P\ =\ 2l\ +\ 2w]


but we are given that:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P\ =\ 42]


and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ l\ = 2w]


so


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2(2w)\ +\ 2w\ =\ 42]


Solve for *[tex \Large w] then calculate *[tex \Large 2w]


Answers are in yards.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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