Question 513194
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rate equals distance divided by time.


Jack's trip:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r\ =\ \frac{d}{2}]


Jill's trip


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r\ -\ 10\ =\ \frac{d}{3}]


Which is to say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r\ =\ \frac{d}{3}\ +\ 10]


Two things each equal to *[tex \Large r] must be equal to each other, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{d}{2}\ =\ \frac{d}{3}\ +\ 10]


Solve for *[tex \Large d]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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