<PRE><B>Question 512742</B>
Without solving, explain what is wrong with the following mixture problem: How many liters of 25% ethanol should be added to 20 liters of 48% ethanol to obtain a solution of 58% ethanol? Now go through an algebraic solution. What happens?
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No amounts of 25% and 48% solutions will give you a 58% solution.
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Attempt:
0.25x + 0.48*20 = 0.58(x+20)
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25x + 48*20 = 58x +58*20
-23x = 10*20
x = -200/23 (amt of 25% solution: MEANINGLESS)
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Cheers,
Stan H.
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