Question 51327
Let  x = width of each pen, assuming that the there will be two pens adjacent to each other, sharing a common length, which is to be 3x.  


If you draw the picture, you will have three lengths (since there is a shared length), each of which is 3x in length.  There will be a total of 4 widths for the two pens, each of which is x.


Total fence required would be
 3(3x) + 4(x) = 65 feet
9x + 4x = 65
13x = 65
x= 5 feet width.
3x= 15 feet length.


The pens are 5 ft by 15 feet.


R^2 at SCC