Question 51316
4x(x^2 + 3x - 2)[Factor using the quadratic formula]
.
 {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
.
 {{{x = (-3 +- sqrt( 3^2-(4)(1)(-2) ))/((2)(1)) }}} 
.
 {{{x = (-3 +- sqrt( 9+8) ))/((2)) }}}
.
{{{x = (-3 +- sqrt( 17) ))/((2)) }}}
.

{{{x = (-3 + sqrt( 17) ))/((2)) }}} = .5615
or
{{{x = (-3 - sqrt( 17) ))/((2)) }}} = -3.562
.
So, the "x"'s are"
4x=0 or  x=0
x=.5615
x=-3.652
Factoring the equation than gives:
(4x)(x-.5615)(x+3.652)
Multiply the factors out and you should get the original equation.