Question 512298
{{{ x^2+7x-5= 0 }}}
<pre>
Put a 1 coefficient on the x² term:

{{{1x^2+7x-5= 0 }}}

Compare to

{{{ax^2+bx+c= 0 }}}

and get a=1, b=7, c=-5 and substitute in:

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}

{{{x = (-7 +- sqrt( 7^2-4*1*(-5) ))/(2*1) }}}

{{{x = (-7 +- sqrt( 49+20 ))/2 }}}

{{{x = (-7 +- sqrt(69 ))/2 }}}

Edwin</pre>