Question 512110
1a.Stella is having a race with Tess. 
Stella gives Tess a 5o foot head start. 
Stella runs at 14.3 feet per second and 
Tess runs at 12.5 feet per second.
----
Tess DATA:
rate = 12.5 ft/sec ; time = t sec ; distance = r*t = 12.5t ft.
---------------
Stella DATA:
rate = 14.3 ft/sec ; time = t sec ; distance = r*t = 14.3t ft.
-------- 
b.Write a system of equations for the two sisters distances.
stella distance = tess distance + 50 ft.
14.3t = 12.5t + 50
------ 
c. How long should the race be in order for it to be a close call.
Solve the equation for "r":
14.3t - 12.5t = 50
1.8t = 50
t = 27.78 sec 
---
Tina's distance 12.5*27.78 = 347.22 ft
Stella's distance 14.3*27.78 = 397.22 ft
=============================================
Cheers,
Stan H.
============