Question 512082
With money problems you have to keep track of the counts and the values.
n = number of nickels
5n = value of nickels in cents
d = number of dimes
10d = value of dimes in cents
q = number of quarters
25q = value of quarters in cents
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5n + 10d + 25q = 450 cents
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d = 2n
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q = d-3
q = 2n -3
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substitute
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5n + 10(2n) + 25(2n-3) = 450
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5n + 20n + 50n -75 = 450
75n = 525
n = 7
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d = 14
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q = 11
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5*7 = 35 cents
10*14 = 140 cents
25*11 = 275 cents
35+140+275 = 450 cents
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Answer: 7 nickels, 14 dimes, and 11 quarters.
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Done.