Question 511920

Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-1,1\right)]. So this means that {{{x[1]=-1}}} and {{{y[1]=1}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(-2,-5\right)].  So this means that {{{x[2]=-2}}} and {{{y[2]=-5}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-5-1)/(-2--1)}}} Plug in {{{y[2]=-5}}}, {{{y[1]=1}}}, {{{x[2]=-2}}}, and {{{x[1]=-1}}}



{{{m=(-6)/(-2--1)}}} Subtract {{{1}}} from {{{-5}}} to get {{{-6}}}



{{{m=(-6)/(-1)}}} Subtract {{{-1}}} from {{{-2}}} to get {{{-1}}}



{{{m=6}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(-1,1\right)] and *[Tex \LARGE \left(-2,-5\right)] is {{{m=6}}}


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Thanks,


Jim