Question 51299
2)For the function y = x2 - 4x - 5
a)Put the function in the form y = a(x - h)2 + k.For the function y = x2 - 4x - 5 
={X^2-2(X)(2)+2^2}-2^2-5
=(X-2)^2-9
A=1....H=2.......K=-9 

b)What is the equation for the line of symmetry or the graph of this function?
X-2=0....OR...X=2 IS THE LINE OF SYMMETRY

c)Graph the function using the equation in part a. Why it is not necessary to plot points to graph when using y = a (x – h)2 + k.
{{{ graph( 500, 500, -10, 10, -10, 10, x^2-4x-5,x^2) }}}
DRAW LINE OF SYMMETRY X=2..PLOT VERTEX AT (2,-9)..PLOT CURVE SYMMETRICALLY ALONG THE LINE OF SYMMETRY TAKING THE 2 INTERCEPT POINTS ON THE X AXIS AS 
X-2=+3 OR -3....THAT IS X=5 AND -1
d)Describe how this graph compares to the graph of y = x2?
IT IS PARALLEL WITH A SHIFT IN VERTEX FROM (0,0) TO (2,-9)