Question 508804
|3x+7| ≻ 16
solve for 2 conditions
for (3x+7)>0
3x+7>16
3x>9
x>3
..
for (3x+7)<0
-3x-7>16
-3x>16+7=23
x<(-23/3)
..
solution:
(-&#8734;, -23/3) U (3, &#8734;)