Question 509765
|12-6y|<48
solve for 2 conditions:
for (12-6y)>0
12-6y<48
-6y<48-12=36
-6y<36
Divide both sides by -6 and reverse inequality sign
y>-6
..
for (12-6y)<0
-12+6y<48
6y<48+12=60
6y<60
y<10
..
solution:
(-6, 10)