Question 510407
15-|3x-12|=<3
solve for 2 conditions
For(3x-12)>0
15-3x+12&#8804;3
-3x&#8804;3-27
-3x&#8804;-24
multiply by -1 and reverse inequality sign
3x&#8805;24
x&#8805;8
..
For(3x-12)<0
15+3x-12&#8804;3
3x&#8804;3-3=0
3x&#8804;0
x&#8804;0
..
solution:
(-&#8734;, 0] U [8, &#8734;)