Question 511426
Graph the equation : f(x)= x^2-5x+6. Clearly label the x-axis, y-axis and origin.
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f(x) = (x-3)(x-2)
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x-intercept: Let y = 0 then x = 2 or x = 3
Plot points at (2,0) and at at (3,0)
The vertex occurs half-way between the x-intercepts
Vertex (5/2 , -1/4) 
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y-intercept: Let x = 0, then y = 6
Plot point at (0,6)
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{{{graph(400,400,-10,10,-2,10,x^2-5x+6)}}}
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State the domain and range of the above function by predicate notation.
Domain: All Real Numbers
Range: y >= -1/4
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cheers,
Stan H.
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