Question 511340
Man's speed	50	mph					
Daughter's speed	65	mph					
Difference in time=		00:15	=>	0.25	hours
0.25*50= 12.5		
Man	will have covered	12.5	miles	before 	daughter 	starts
catch up distance=		12.5	miles				
catch up speed =		65	-50	mph			
catch up speed =		15	mph				
Catchup time = catchup distance/catch up speed							
catch up time=		12.5	/	15			
catch up time=		0.83	hours	  => 49.8 minutes  

50 minutes