Question 511222
Table 1		White	Black	Hispan  Asian	Foreign	Total
	Dept.1	4	0	1	1	2	8
	Dept.2	2	4	1	1	0	8
	Dept.3	1	2	3	1	1	8
	Dept.4	4	0	1	1	2	8
	Dept.5	3	2	1	0	2	8
	Total	14	8	7	4	7	40
							
Table 2		Female	Male	Total			
	Black	6	2	8			
	White	6	8	14			
	Hispan	3	4	7			
	Asian	2	2	4			
	Foreign	2	5	7			
	Total	19	21	40			

From Table 1, what is the probability of choosing an African American employee?:::8/40 = 20%
From Table 2, what is the probability of choosing an Asian female given all females?:: 2/19 = 10.5%
From Table 1, what is the probability of choosing a White employee from Dept. 2 and then an Hispanic employee from Dept. 3?:: (2+3)/40 = 20%
    From Table 2, what is the probability of choosing a Black male or Foreign male?::: no Foreign column listed
From Table 1, what is the probability of choosing a Foreigner or an Hispanic both from Department 5?::: (2+1)/40 = 7.5%
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Cheers,
Stan H.