Question 51260
f(x) = (x - 1)^2 + 2
y = (x - 1)^2 + 2
x = (y - 1)^2 + 2
x - 2 = (y - 1)^2
+-{{{sqrt(x - 2)}}} = y - 1
+-{{{sqrt(x - 2)}}} + 1 = y
Domain: {x|{{{x>=2}}}}
Range: {y|all reals}
{{{graph(600,600,-10,10,-10,10,x,(x-1)^2+2,sqrt(x-2)+1,-sqrt(x-2)+1)}}}