<PRE><B>Question 511217</B>
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Nope, impossible situation.  Angle 2 complementary to Angle 1 implies that both Angle 2 and Angle 1 are less than 90 in measure.  Angle 2 being less than 90 means that supplementary Angle 3 must be greater than 90.  Hence 3 and 1 cannot possibly be congruent.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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