Question 511158
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Since your equations are in Standard form *[tex \Large \left(Ax\ +\ By\ =\ C\right)], you can determine the slope of each line by calculating*[tex \Large \frac{-A}{B}].  Calculate the slope of both of your lines.


If the slopes are equal, then the lines are parallel.


If the slopes are negative reciprocals of each other, then the lines are perpendicular.


Otherwise, neither.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1\ \parallel\ L_2 \ \ \Leftrightarrow\ \ m_1\ =\ m_2]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1\ \perp\ L_2 \ \ \Leftrightarrow\ \ m_1\ =\ -\frac{1}{m_2}\ \text{ and } m_1,\, m_2\, \neq\, 0]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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