Question 510651
Find the values of the trigonometric functions of θ 
from the information given.
cos &#952; = &#8722; 3/4, tan &#952; < 0
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Cos negative and tan negative means theta is in the 2nd  Quadrant
where x is negative and y is positive
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cos = x/r = -3/4 implies that x = -3 and r = 4
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y = sqrt[r^2-x^2] = sqrt[4^2-3^2] = sqrt(7)
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sin = y/r = sqrt(7)/4
cos = x/r = -3/4
tan = y/x = sqrt(7)/-3 = -sqrt(7)/3
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csc = r/y = 4/sqrt(7)
sec = r/x = -4/3
cot = x/y = -3/sqrt(7)
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Cheers,
Stan H.
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