Question 510533
You can use the rules for exponents:
{{{ (a^b)^c = a^(b*c) }}}
{{{ (a*b)^c = a^c*b^c }}}
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{{{ (8x^6*y^9)^(2/3)/(16*x^8*y^(-4))^(1/2) }}}
(note that {{{ 8 = 2^3 }}} and {{{ 16 = 4^2 }}} )
( and {{{ (2^3)^(2/3) = 4 }}} and {{{ (4^2)^(1/2) = 4 }}} )
{{{ (4x^4*y^6) / (4x^4*y^(-2)) }}}
{{{ ((4x^4) / (4x^4))*((y^6) / (y^(-2))) }}}
{{{ y^6*y^2 }}}
{{{ y^8 }}}
Unless I made a mistake- I would get another opinion, too