Question 51233
It may be helpful to find a way to eliminate the p, and then eliminate the q, and write two equations, one for p and one for q.


First, if you add the two equations together, you can eliminate the p, and get

x=2+p-2q
y=3-p+3q 
x+y = 5 + q, so q = x+y-5


Second, to eliminate the q, multiply both sides of the first equation by 3, and the second equation by 2:
3(x)=3(2+p-2q)
2(y)=2(3-p+3q) 


3x= 6 +3p-6q
2y = 6-2p+6q


3x+2y = 12 +p, so p=3x+2y - 12


There you have it:
p=3x+2y-12
q=x+y-5


I have no idea how to check this, unless you solve for x and y to see if you come back with the same equations that you started with.  It looks like Linear Algebra to me.  Hey, I gotta go to work this morning!!


R^2 at SCC