Question 510227
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The diagonals of a parallelogram bisect each other, therefore, the point of intersection is the midpoint of either.  Use the midpoint formulas with the endpoints of either diagonal (the segments AC and BD are the diagonals), to find the midpoint, and therefore the point of intersection of the diagonals.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x_m\ = \frac{x_1 + x_2}{2}] and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y_m\ = \frac{y_1 + y_2}{2}]


where *[tex \Large \left(x_1,y_1\right)] and *[tex \Large \left(x_2,y_2\right)] are the coordinates of the endpoints of the segment in question.


Hint:  The arithmetic is lots easier if you do segment BD.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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